Integrand size = 26, antiderivative size = 45 \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=\frac {a x}{c-i d}+\frac {a \log (c \cos (e+f x)+d \sin (e+f x))}{(i c+d) f} \]
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Time = 0.09 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3612, 3611} \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=\frac {a \log (c \cos (e+f x)+d \sin (e+f x))}{f (d+i c)}+\frac {a x}{c-i d} \]
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Rule 3611
Rule 3612
Rubi steps \begin{align*} \text {integral}& = \frac {a x}{c-i d}+\frac {a \int \frac {d-c \tan (e+f x)}{c+d \tan (e+f x)} \, dx}{i c+d} \\ & = \frac {a x}{c-i d}+\frac {a \log (c \cos (e+f x)+d \sin (e+f x))}{(i c+d) f} \\ \end{align*}
Time = 0.29 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.87 \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=\frac {a (-\log (i+\tan (e+f x))+\log (c+d \tan (e+f x)))}{(i c+d) f} \]
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Time = 0.26 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.44
method | result | size |
norman | \(\frac {a x}{-i d +c}+\frac {i a \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2 f \left (-i d +c \right )}-\frac {i a \ln \left (c +d \tan \left (f x +e \right )\right )}{f \left (-i d +c \right )}\) | \(65\) |
derivativedivides | \(\frac {a \left (\frac {\frac {\left (i c -d \right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2}+\left (i d +c \right ) \arctan \left (\tan \left (f x +e \right )\right )}{c^{2}+d^{2}}-\frac {\left (i c -d \right ) \ln \left (c +d \tan \left (f x +e \right )\right )}{c^{2}+d^{2}}\right )}{f}\) | \(83\) |
default | \(\frac {a \left (\frac {\frac {\left (i c -d \right ) \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2}+\left (i d +c \right ) \arctan \left (\tan \left (f x +e \right )\right )}{c^{2}+d^{2}}-\frac {\left (i c -d \right ) \ln \left (c +d \tan \left (f x +e \right )\right )}{c^{2}+d^{2}}\right )}{f}\) | \(83\) |
risch | \(-\frac {2 a x}{i d -c}-\frac {2 i a x}{i c +d}-\frac {2 i a e}{f \left (i c +d \right )}+\frac {a \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {i d +c}{i d -c}\right )}{f \left (i c +d \right )}\) | \(87\) |
parallelrisch | \(\frac {2 i x a d f +i \ln \left (1+\tan ^{2}\left (f x +e \right )\right ) a c -2 i \ln \left (c +d \tan \left (f x +e \right )\right ) a c +2 x a c f -\ln \left (1+\tan ^{2}\left (f x +e \right )\right ) a d +2 \ln \left (c +d \tan \left (f x +e \right )\right ) a d}{2 f \left (c^{2}+d^{2}\right )}\) | \(91\) |
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Time = 0.24 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.96 \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=\frac {a \log \left (\frac {{\left (i \, c + d\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + i \, c - d}{i \, c + d}\right )}{{\left (i \, c + d\right )} f} \]
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Time = 0.69 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.98 \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=- \frac {i a \log {\left (\frac {c + i d}{c e^{2 i e} - i d e^{2 i e}} + e^{2 i f x} \right )}}{f \left (c - i d\right )} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 90 vs. \(2 (41) = 82\).
Time = 0.42 (sec) , antiderivative size = 90, normalized size of antiderivative = 2.00 \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=\frac {\frac {2 \, {\left (a c + i \, a d\right )} {\left (f x + e\right )}}{c^{2} + d^{2}} + \frac {2 \, {\left (-i \, a c + a d\right )} \log \left (d \tan \left (f x + e\right ) + c\right )}{c^{2} + d^{2}} + \frac {{\left (i \, a c - a d\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right )}{c^{2} + d^{2}}}{2 \, f} \]
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Time = 0.37 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.51 \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=-\frac {\frac {i \, a \log \left (c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 2 \, d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - c\right )}{c - i \, d} - \frac {2 i \, a \log \left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + i\right )}{c - i \, d}}{f} \]
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Time = 6.18 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.96 \[ \int \frac {a+i a \tan (e+f x)}{c+d \tan (e+f x)} \, dx=-\frac {a\,\mathrm {atan}\left (\frac {c\,1{}\mathrm {i}-d+d\,\mathrm {tan}\left (e+f\,x\right )\,2{}\mathrm {i}}{c-d\,1{}\mathrm {i}}\right )\,2{}\mathrm {i}}{f\,\left (d+c\,1{}\mathrm {i}\right )} \]
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